Joule's law of heating
- CBSE · NCERT Class 10, Ch 11 Electricity
Joule's law of heating says the heat produced in a resistor is H = I²Rt, where I is the current, R the resistance and t the time.
When current flows through a resistor, the source's energy turns into heat. This is the heating effect of electric current. It is why a heater coil glows and an electric iron gets hot. The law has three parts. The heat produced is directly proportional to:
- the square of the current, for a given resistance;
- the resistance, for a given current;
- the time for which the current flows.
H is in joules (J) when I is in amperes, R in ohms and t in seconds.
A small example
- A current of 2 A flows through a 10 Ω resistor for 30 s.
- H = I²Rt = (2 A)² × 10 Ω × 30 s = 1200 J.
- Double the current to 4 A: H = (4 A)² × 10 Ω × 30 s = 4800 J.
Twice the current gives four times the heat, because the current is squared.
Where marks go
Question 34 of CBSE's 2026-27 Science sample paper offers this law as one side of an internal choice. The 2026-27 Science marking scheme gives 1 mark for the statement, printed with all three parts and H = I²Rt. The second mark is for the effect of doubling R at the same current. The heat doubles too.
So a bare formula is not the full statement. The scheme lists the three conditions in words. Keep "for a given resistance" and "for a given current" in your answer.
Sources
Facts last checked against these sources on 30 September 2026.
- Science, Class X (2026-27), Chapter 11: Electricity · NCERT
- Science (086) Marking Scheme, Class X 2026-27 - Question 34 · CBSE Academic Unit
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